One skyscraper is 100dm. At some time the shadow of a 1dm high pole is 33dm long from the light of the sun. What will be the angle of elevation of sun and the length of the shadow and the shadow of the skyscraper at the same time.
Solution: Let BC is a skyscraper of height 100dm. and DE is a pole of height 9dm. Let elevation angle of sun is θ. According to question, ∠DAE=∠CAB=θ and AE=33dm From right angled ΔDEA tanθ=AEDE =339 =3 =tan600=θ=600 Hence, angle of elevation of sun =600 Again from right angled ΔABC, tanθ=ABBC tan600=AB100 3=AB100 AB=3100 Hence, angle of elevation of sun is 600 and length of shadow of skyscraper 3100 decimeter.