Of the members of three athletic teams in a certain school, 21 are in the basketball team, 26 in hockey team and 29 in the football team. 14 play hockey and basket ball, 15 play hockey and football, 12 play football and basketball and 8 play all the three games bow many members are there in all?

Question

Of the members of three athletic teams in a certain school, 21 are in  the basketball team, 26 in hockey team and 29 in the football team. 14 play  hockey and basket ball, 15 play hockey and football,  12 play football and basketball and 8 play all the three games bow many  members are there in all?

Filo · Accepted Answer

Solution: Let B is the set of members who are in basketball team, F is the set of members who are in Football team, H is the set of members who are in hockey team.Then,n(B∪F∪H)=n(B)+n(F)+n(H)−n(B∩F)−n(F∩H)−n(B∩H)+n(B∩F∩H)∴n(B∪F∪H)=21+26+29−14−15−12+8⇒n(B∪F∪H)=43So, there are total 43 members in all.

Question Text	Of the members of three athletic teams in a certain school, 21 are in the basketball team, 26 in hockey team and 29 in the football team. 14 play hockey and basket ball, 15 play hockey and football, 12 play football and basketball and 8 play all the three games bow many members are there in all?
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Of the members of three athletic teams in a certain school, 21 are in the basketball team, 26 in hockey team and 29 in the football team. 14 play hockey and basket ball, 15 play hockey and football, 12 play football and basketball and 8 play all the three games bow many members are there in all?

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