(lim)x→∞(e1−1+xx)x is equal to (a) 1−ee (b) 0 (c) e1−ee (d) does not exist

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Question

$(lim)_{x \to \infty} (\frac{1}{e} - \frac{x}{1 + x})^{x}$ is equal to (a) $\frac{e}{1 - e}$ (b) 0 (c) $\frac{e}{e ^{1 - e}}$ (d) does not exist

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Harper Discussed

(lim)_{x \to \infty} (\frac{1}{e} - \frac{x}{1 + x})^{x}

is equal to (a)

\frac{e}{1 - e}

(b) 0 (c)

\frac{e}{e ^{1 - e}}

(d) does not exist

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Question Text

(lim)_{x \to \infty} (\frac{1}{e} - \frac{x}{1 + x})^{x}

is equal to (a)

\frac{e}{1 - e}

(b) 0 (c)

\frac{e}{e ^{1 - e}}

(d) does not exist