Let Sn=1+2+3++n and Pn=S2−1S2S3−1S3˙S4−1S4˙Sn−1Sn Where n∈N,(n≥2)˙ Then \displaystyle{\left(\text{lim}\right)}_{{{x}\vec{\infty}}}{P}_{{n}}=_{_}__{_}_

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Let {S}_{{n}}={1}+{2}+{3}++{n} and {P}_{{n}}={{{S}_{{2}}}}{{{S

Question

Let $S_{n} = 1 + 2 + 3 + + n$ and $P_{n} = \frac{S _{2}}{S _{2} - 1} \frac{S _{3} ˙}{S _{3} - 1} \frac{S _{4} ˙}{S _{4} - 1} \frac{S _{n}}{S _{n} - 1}$ Where $n \in N, (n \geq 2) ˙$ Then \displaystyle{\left(\text{lim}\right)}_{{{x}\vec{\infty}}}{P}_{{n}}=_{_}__{_}_

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Elijah Discussed

Let

S_{n} = 1 + 2 + 3 + + n

and

P_{n} = \frac{S _{2}}{S _{2} - 1} \frac{S _{3} ˙}{S _{3} - 1} \frac{S _{4} ˙}{S _{4} - 1} \frac{S _{n}}{S _{n} - 1}

Where

n \in N, (n \geq 2) ˙

Then \displaystyle{\left(\text{lim}\right)}_{{{x}\vec{\infty}}}{P}_{{n}}=_{_}__{_}_

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Question Text

Let

S_{n} = 1 + 2 + 3 + + n

and

P_{n} = \frac{S _{2}}{S _{2} - 1} \frac{S _{3} ˙}{S _{3} - 1} \frac{S _{4} ˙}{S _{4} - 1} \frac{S _{n}}{S _{n} - 1}

Where

n \in N, (n \geq 2) ˙

Then \displaystyle{\left(\text{lim}\right)}_{{{x}\vec{\infty}}}{P}_{{n}}=_{_}__{_}_