Question
Let LMNP be a parallelogram and NR be perpendicular to LP. If the area of the parallelogram is six times the area of ΔRNP and RP = 6 cm then LR is equal to
Found 8 tutors discussing this question
Discuss this question LIVE
14 mins ago
Text solutionVerified
(b): by given condition, Area of parallelogram =6×area of ΔNPR ∴NR×PL=6×12×NR×pR ⇒PL=3PR (here,PL=PR+RL) ⇒ PR+RL=3PR ⇒RL=2PR=2×6=12cm.
Was this solution helpful?
150
Share
Report
One destination to cover all your homework and assignment needs
Learn Practice Revision Succeed
Instant 1:1 help, 24x7
60, 000+ Expert tutors
Textbook solutions
Big idea maths, McGraw-Hill Education etc
Essay review
Get expert feedback on your essay
Schedule classes
High dosage tutoring from Dedicated 3 experts
Practice questions from similar books
Question 1
In ΔPQR, the line drawn from the vertex P intersects QR at a point S. If QR = 4.5 cm and SR = 1.5 cm then the ratios of the area of triangle PQS and triangle PSR isQuestion 2
ABCD is a trapezium with parallel sides AB = 2cm and DC = 3cm. E and F are the mid- points of the non-parallel sides. The ratio of area of ABFE to area of EFCD is Stuck on the question or explanation?
Connect with our math tutors online and get step by step solution of this question.
231 students are taking LIVE classes
Question Text | Let LMNP be a parallelogram and NR be perpendicular to LP. If the area of the parallelogram is six times the area of ΔRNP and RP = 6 cm then LR is equal to |
Answer Type | Text solution:1 |
Upvotes | 150 |