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In the given figure below, two chords AB and CD of a circle with centre O, intersect each other at P. If ∠AOD=120∘and ∠BOC=50∘, then the value of ∠APC is
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(d): ∠AOD=120∘ ∠ACD=∠ACP=1202=60∘ (The angle subtended at the centre is twice to that, of angle at: the circumference by the same arc) Again ∠BOC=50∘ ∴ ∠BAC=502=25∘=∠PAC ∴ ∠APC=180∘−60∘−25=95∘
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Question Text | In the given figure below, two chords AB and CD of a circle with centre O, intersect each other at P. If ∠AOD=120∘and ∠BOC=50∘, then the value of ∠APC is |
Answer Type | Text solution:1 |
Upvotes | 150 |