Question
In the given figure below, Chords AB and CD of a circle intersect at E and are perpendicular to each other. Segments AE, EB and ED are of lengths 2 cm, 6 cm and 3 cm respectively. Then the length of the diameter of the circle (in cm) is
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(a): AE=2cm EB=6cm ED=3cm ∴ AE×EB=DE×EC ⇒ EC=2×63=4cm ∴ Diameter =72+42−−−−−−√= 49+16−−−−−−√ =65−−√ cm
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Question Text | In the given figure below, Chords AB and CD of a circle intersect at E and are perpendicular to each other. Segments AE, EB and ED are of lengths 2 cm, 6 cm and 3 cm respectively. Then the length of the diameter of the circle (in cm) is |
Answer Type | Text solution:1 |
Upvotes | 151 |