Question
In the given figure an isosceles triangle, the measure of each of equal sides is 10 cm and the angle between them is 45°, the area of the triangle is
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(c): AB=AC=10cm Area=12bcsinA=12×10×10sin45∘ =502√=50×2√2√×2√=252√cm2
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Question Text | In the given figure an isosceles triangle, the measure of each of equal sides is 10 cm and the angle between them is 45°, the area of the triangle is |
Answer Type | Text solution:1 |
Upvotes | 150 |