In the following, state whether $A=B$or not:(i) $A=\left\{a,b,c,d\right\}$ $B=\left\{d,c,b,a\right\}$(ii) $A=\left\{4,8,12,16\right\}$ $B=\left\{8,4,16,18\right\}$(iii) $A=\left\{2,4,6,8,10\right\}$ B = {x: x is po

Solution: $\left(i\right)$ - Both sets $A$ and $B$ are having same elements. Only order is different that means $A=B$.
$\left(ii\right)$ - Set $A$ contains 12 that is not present in Set $B$ and Set $B$ contains 18 that is not present in Set $A$. So, $A\ne B$.
$\left(iii\right)$ - Set $A$ contains 10 that is not present in Set $B$ as Set $B$ contain all elements less than 10.So, $A\ne B$.
$\left(iv\right)$ - Set $B$ contains 15,25 etc. that are not multiple of 10.So, $A\ne B$.