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In the figure, PQ and RS are two mirrors placed parallel to ea

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In the figure, $PQ$ and $RS$ are two mirrors placed parallel to each other. An incident ray $A B$ strikes the mirror $PQ$ at $B$ , the reflected ray moves along the path $BC$ and strikes the mirror $RS$ at $C$ and again reflects back along $C D$ . Prove that $A B ∥ C D$ .

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In the figure,

PQ

and

RS

are two mirrors placed parallel to each other. An incident ray

A B

strikes the mirror

PQ

B

, the reflected ray moves along the path

BC

and strikes the mirror

RS

C

and again reflects back along

C D

. Prove that

A B ∥ C D

8 mins ago

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8 mins ago

Text solutionVerified

At surface

B,

∠1 = ∠2

(property of reflection)

At surface

C,

∠3 = ∠4

(property of reflection))

As the sum of the angles are equal

A B

is parallel to

C D,

∠2 = ∠3

(Alternate interior angles)

∠1 + ∠2 = ∠3 + ∠4

Alternate interior angles are equal.

∴ A B ∥ C D

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Question Text	In the figure, $PQ$ and $RS$ are two mirrors placed parallel to each other. An incident ray $A B$ strikes the mirror $PQ$ at $B$ , the reflected ray moves along the path $BC$ and strikes the mirror $RS$ at $C$ and again reflects back along $C D$ . Prove that $A B ∥ C D$ .
Answer Type	Text solution:1
Upvotes	150

In the figure, PQ and RS are two mirrors placed parallel to each other. An incident ray AB strikes the mirror PQ at B, the reflected ray moves along the path BC and strikes the mirror RS at C and again reflects back along CD. Prove that AB∥CD.

Text solutionVerified

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In the figure, $PQ$ and $RS$ are two mirrors placed parallel to each other. An incident ray $A B$ strikes the mirror $PQ$ at $B$ , the reflected ray moves along the path $BC$ and strikes the mirror $RS$ at $C$ and again reflects back along $C D$ . Prove that $A B ∥ C D$ .