In figure D is a point on side BC of a ΔABCsuch that CDBD=ACAB. Prove that AD is the bisector of ∠BAC.

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Question

In figure D is a point on side BC of a $Δ A B C$ such that $\frac{B D}{C D} = \frac{A B}{A C}$ . Prove that AD is the bisector of $∠ B A C$ .

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In figure D is a point on side BC of a

Δ A B C

such that

\frac{B D}{C D} = \frac{A B}{A C}

. Prove that AD is the bisector of

∠ B A C

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Question Text

In figure D is a point on side BC of a

Δ A B C

such that

\frac{B D}{C D} = \frac{A B}{A C}

. Prove that AD is the bisector of

∠ B A C