Question
In Fig. 9.22, ABCD is a quadrilateral and and also BE meets DC produced at E. Show that area of is equal to the area of the quadrilateral ABCD.
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Solution: Lets proof BE||AC and take other things given.
area(ABCD)=area(ACD)+area(ABC)
area(ADE)=area(ACD)+area(AEC)
So, area(ABC)=area(AEC)
According theorem 9.2
BE||AC.
area(ABCD)=area(ACD)+area(ABC)
area(ADE)=area(ACD)+area(AEC)
So, area(ABC)=area(AEC)
According theorem 9.2
BE||AC.
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Question Text | In Fig. 9.22, ABCD is a quadrilateral and and also BE meets DC produced at E. Show that area of is equal to the area of the quadrilateral ABCD. |
Answer Type | Text solution:1 |
Upvotes | 150 |