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If Zeba was younger by 5 years than what she really is, then t

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If Zeba was younger by $5$ years than what she really is, then the square of her age (in years) would have been $11$ more than five times her actual age. What is her age now?

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Noah Discussed

If Zeba was younger by

5

years than what she really is, then the square of her age (in years) would have been

11

more than five times her actual age. What is her age now?

13 mins ago

Discuss this question LIVE

13 mins ago

Text solutionVerified

Let the present age of Zeba be

x

years
Age before

5

years

= (x - 5)

years
According to given condition

\Rightarrow

(x - 5)^{2} = 5 x + 11 \Rightarrow x^{2} + 25 - 10 x = 5 x + 11

\Rightarrow

x^{2} - 10 x - 5 x + 25 - 11 = 0

\Rightarrow

x (x - 14) - 1 (x - 14) = 0

\Rightarrow

(x - 1) (x - 14) = 0

\Rightarrow

x - 1 = 0

x - 14 = 0

x = 1

x = 14

But present age cannot be

1

year
Present age of Zeba is

14

years.

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Question Text	If Zeba was younger by $5$ years than what she really is, then the square of her age (in years) would have been $11$ more than five times her actual age. What is her age now?
Answer Type	Text solution:1
Upvotes	150