If X and Y are two sets such that X has 40 elements, X∪Yhas 60 elements and X∩Yhas 10 elements, how many elements does Y have?

Solution: Here, n(X)=40n(X∪Y)=60n(X∩Y)=10We know,n(X∪Y)=n(X)+n(Y)−n(X∩Y)⇒60=40+n(Y)−10⇒n(Y)=30So, Set Y has 30 elements.

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If X and Y are two sets such that X has 40 elements, {X}{Y}has

Question

If X and Y are two sets such that X has 40 elements, $X \cup Y$ has 60 elements and $X \cap Y$ has 10 elements, how many elements does Y have?

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Emma Discussed

If X and Y are two sets such that X has 40 elements,

X \cup Y

has 60 elements and

X \cap Y

has 10 elements, how many elements does Y have?

8 mins ago

Discuss this question LIVE

8 mins ago

Solution: Here,

n (X) = 40

n (X \cup Y) = 60

n (X \cap Y) = 10

We know,

n (X \cup Y) = n (X) + n (Y) - n (X \cap Y)

\Rightarrow 60 = 40 + n (Y) - 10

\Rightarrow n (Y) = 30

So, Set Y has

30

elements.

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Question Text	If X and Y are two sets such that X has 40 elements, $X \cup Y$ has 60 elements and $X \cap Y$ has 10 elements, how many elements does Y have?
Answer Type	Text solution:1
Upvotes	150