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If two equal chords of a circle intersect within the circle, prove that the segments of one chord are equal to corresponding segments of other chord.

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Text SolutionText solutionverified iconVerified

Drop a perpendicular from to both chords and

In and 

As chords are equal, perpendicular from centre would also be equal.


is common.


  (RHS Congruence)


                                              ......................(1)

              (Perpendicular from centre bisects the chord)

Similarly ,

As


                                                .........................(2)

From (1) and (2)


 

                   (Half the length of equal chords are equal)



Therefore ,   and  is proved.
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Question Text
If two equal chords of a circle intersect within the circle, prove that the segments of one chord are equal to corresponding segments of other chord.
Answer TypeText solution:1
Upvotes151