Question
If the plane 2ax−3ay+4az+6=0 passes through the midpoint of the line joining the centres of the spheres x2+y2+z2+6x−8y−2z=13 and x2+y2+z2−10x+4y−2z=8 then a equals
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[c] Plane 2ax−3ay+4az+6=0 passes through the midpoint of the centre of spheres x2+y2+z2+6x−8y−2z=13 and x2+y2+z2−10x+4y−2z=8 Respectively center of spheres are (−3,4,1) and (5,−2,1). Midpoint of centres is (1,1,1). Satisfying this in the equation of plane, we get 2a−3a+4a+6=0⇒a=−2.
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Question Text | If the plane 2ax−3ay+4az+6=0 passes through the midpoint of the line joining the centres of the spheres x2+y2+z2+6x−8y−2z=13 and x2+y2+z2−10x+4y−2z=8 then a equals |
Answer Type | Text solution:1 |
Upvotes | 150 |