If $^{n} P_{r} =^{n} P_{r + 1} a n d^{n} C_{r} =^{n} C_{r - 1,}$ then the value of $n + r$ is.

Views: 1,047 students

Found 6 tutors discussing this question

Camila Discussed

^{n} P_{r} =^{n} P_{r + 1} a n d^{n} C_{r} =^{n} C_{r - 1,}

then the value of

n + r

is.

14 mins ago

Discuss this question LIVE

14 mins ago

One destination to cover all your homework and assignment needs

Learn Practice Revision Succeed

Instant 1:1 help, 24x7

60, 000+ Expert tutors

Textbook solutions

Big idea maths, McGraw-Hill Education etc

Essay review

Get expert feedback on your essay

Schedule classes

High dosage tutoring from Dedicated 3 experts

Trusted by 4 million+ students

Stuck on the question or explanation?

Connect with our math tutors online and get step by step solution of this question.

231 students are taking LIVE classes

Question Text

^{n} P_{r} =^{n} P_{r + 1} a n d^{n} C_{r} =^{n} C_{r - 1,}

then the value of

n + r

is.

Filo tutor solution