If logr6=m and logr3=n then is logr(r/2)is equal to

m−n+1

m+n−1

m−n−1

m−n+1

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If logr6=m and logr3=n then is logr(r/2)is equal to

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(d): Given, logr6=m and logr3=n ∴logr6−logr(2×3) =logr2 +logr3 ∴logr3+logr2=m ⇒n+logr2=m ⇒logr2=m−n =1−m+n

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Question Text	If logr6=m and logr3=n then is logr(r/2)is equal to
Answer Type	Text solution:1
Upvotes	150