If x→2−lim2−e∣x+2∣1ae∣x+2∣1−1=x→2+limsin(x5+32x4−16), then a is

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If $x \to 2^{-} lim \frac{a e ^{\frac{1}{∣ x + 2 ∣}} - 1}{2 - e ^{\frac{1}{∣ x + 2 ∣}}} = x \to 2^{+} lim sin (\frac{x ^{4} - 16}{x ^{5} + 32})$ , then a is

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Henry Discussed

x \to 2^{-} lim \frac{a e ^{\frac{1}{∣ x + 2 ∣}} - 1}{2 - e ^{\frac{1}{∣ x + 2 ∣}}} = x \to 2^{+} lim sin (\frac{x ^{4} - 16}{x ^{5} + 32})

, then a is

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Question Text

x \to 2^{-} lim \frac{a e ^{\frac{1}{∣ x + 2 ∣}} - 1}{2 - e ^{\frac{1}{∣ x + 2 ∣}}} = x \to 2^{+} lim sin (\frac{x ^{4} - 16}{x ^{5} + 32})

, then a is