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If in a triangle ABC, sinA4=sinB5=sinC6, then the value of cosA+cosB+cosCis equal to
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We have sinA4=sinB5=sinC6⇒a4=b5=c6=λ (say) ∴ a=4λ,b=5λ,c=6λ Now cosA+cosB+cosC = b2+c2−a22bc+c2+a2−b22ac+a2+b2−c22ab = 1240λ3{4λ(45λ2+5λ(27λ2)+6λ(5λ2)}=6948.
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| Question Text | If in a triangle ABC, sinA4=sinB5=sinC6, then the value of cosA+cosB+cosCis equal to |
| Answer Type | Text solution:1 |
| Upvotes | 150 |
