If in a triangle $A B C,$ the side $c$ and the angle $C$ remain constant, while the remaining elements are changed slightly, show that $\frac{d a}{cos A} + \frac{d b}{cos B} = 0 .$

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If in a triangle

A B C,

the side

c

and the angle

C

remain constant, while the remaining elements are changed slightly, show that

\frac{d a}{cos A} + \frac{d b}{cos B} = 0 .

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Question Text

If in a triangle

A B C,

the side

c

and the angle

C

remain constant, while the remaining elements are changed slightly, show that

\frac{d a}{cos A} + \frac{d b}{cos B} = 0 .

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