If f is a continuous function on [0,1], differentiable in (0, 1) such that f(1)=0, then there exists some c∈(0,1) such that cfprime(c)−f(c)=0 cfprime(c)+cf(c)=0 fprime(c)−cf(c)=0 cfprime(c)+f(c)=0

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If {f} is a continuous function on {[{0},{1}]}, differentiable

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If $f$ is a continuous function on $[0, 1],$ differentiable in (0, 1) such that $f (1) = 0,$ then there exists some $c \in (0, 1)$ such that $c f^{p r i m e} (c) - f (c) = 0$ $c f^{p r i m e} (c) + c f (c) = 0$ $f^{p r i m e} (c) - c f (c) = 0$ $c f^{p r i m e} (c) + f (c) = 0$

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f

is a continuous function on

[0, 1],

differentiable in (0, 1) such that

f (1) = 0,

then there exists some

c \in (0, 1)

such that

c f^{p r i m e} (c) - f (c) = 0

c f^{p r i m e} (c) + c f (c) = 0

f^{p r i m e} (c) - c f (c) = 0

c f^{p r i m e} (c) + f (c) = 0

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Question Text

f

is a continuous function on

[0, 1],

differentiable in (0, 1) such that

f (1) = 0,

then there exists some

c \in (0, 1)

such that

c f^{p r i m e} (c) - f (c) = 0

c f^{p r i m e} (c) + c f (c) = 0

f^{p r i m e} (c) - c f (c) = 0

c f^{p r i m e} (c) + f (c) = 0