If dxdy=(ey−x)−1, where y(0)=0 , then y is expressed explicitly as

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If {{.{d}{y}.}}{{.{d}{x}.}}={({e}^{{y}}-{x})}^{{-{1}}}, where

Question

If $\frac{d y}{d x} = (e^{y} - x)^{- 1},$ where $y (0) = 0$ , then $y$ is expressed explicitly as

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\frac{d y}{d x} = (e^{y} - x)^{- 1},

where

y (0) = 0

, then

y

is expressed explicitly as

15 mins ago

Discuss this question LIVE

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Question Text

\frac{d y}{d x} = (e^{y} - x)^{- 1},

where

y (0) = 0

, then

y

is expressed explicitly as