If $A B C D$ is a parallelogram, then prove that $a r (A B D) = a r (B C D) = a r (A B C) = a r (A C D) = \frac{1}{2} a r (∣ ∣^{g m} A B C D)$

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A B C D

is a parallelogram, then prove that

a r (A B D) = a r (B C D) = a r (A B C) = a r (A C D) = \frac{1}{2} a r (∣ ∣^{g m} A B C D)

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A B C D

is a parallelogram, then prove that

a r (A B D) = a r (B C D) = a r (A B C) = a r (A C D) = \frac{1}{2} a r (∣ ∣^{g m} A B C D)

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