Given : 5cosA−12sinA=0; evaluate :2cosA−sinAsinA+cosA is m17, m is

5cosA−12sinA=0tanA=125Now, 2cosA−sinAsinA+cosA Multiply and divide by cosA= 2−tanAtanA+1 = 2−125125+1 = 1224−5125+12 = 1917

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Given : 5, , A, -, 12, , A, =, 0; evaluate : {, A, +, , A}{2,

Question

Given : $5 cos A - 12 sin A = 0$ ; evaluate :
$\frac{sin A + cos A}{2 cos A - sin A}$ is $\frac{17}{m}$ , m is

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Mila Discussed

Given :

5 cos A - 12 sin A = 0

; evaluate :

\frac{sin A + cos A}{2 cos A - sin A}

\frac{17}{m}

, m is

8 mins ago

Discuss this question LIVE

8 mins ago

5 cos A - 12 sin A = 0

tan A = \frac{5}{12}

Now,

\frac{sin A + cos A}{2 cos A - sin A}

Multiply and divide by

cos A

\frac{tan A + 1}{2 - tan A}

\frac{\frac{5}{12} + 1}{2 - \frac{5}{12}}

\frac{\frac{5 + 12}{12}}{\frac{24 - 5}{12}}

\frac{17}{19}

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Question Text	Given : $5 cos A - 12 sin A = 0$ ; evaluate : $\frac{sin A + cos A}{2 cos A - sin A}$ is $\frac{17}{m}$ , m is
Answer Type	Text solution:1
Upvotes	150