Question
From the top of a tower of height 50 m, the angles of depression of the top and bottom of a pole are and respectively. Find:
i) how far the pole is from the bottom of the tower?
ii) the height of the pole.
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Text solutionVerified
In this fig, AB is the tower.
CD is the pole.
The distance between the tower and the pole is BC
In right angle triangle ABC, one angle is 45
Hence the other angle is 180-90-45=45
Hence it is a 45 -45- 90 triangle.
BC=AB=50m.
Hence the distance between the tower and the pole is 50m.
Now in rt.angled ,
AED is a 30-60-90 Triangle.
Hence
Hence height of the pole
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Question Text | From the top of a tower of height 50 m, the angles of depression of the top and bottom of a pole are and respectively. Find: i) how far the pole is from the bottom of the tower? ii) the height of the pole. |
Answer Type | Text solution:1 |
Upvotes | 150 |