Class 11

Math

Algebra

Permutations and Combinations

From a committee of $8$ persons, in how many ways can we choose a chairman and a vice chairman assuming one person can not hold more than one position?

Here, the number of ways of choosing a chairman is the permutation of $8$ different objects taken $2$ at a time.

Thus, required number of ways= $_{8}P_{2}=(8−2)!8! =6!8! =6!8×7×6! =8×7=56$