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Find the value of K so that (K+2), (4K - 6) and (3K - 6) are t

Question

Find the value of K so that $(K + 2), (4 K - 6)$ and $(3 K - 6)$ are three continuous terms of AP.

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Elijah Discussed

Find the value of K so that

(K + 2), (4 K - 6)

and

(3 K - 6)

are three continuous terms of AP.

5 mins ago

Discuss this question LIVE

5 mins ago

Text solutionVerified

Given

(K + 2), (4 K - 6)

and

(3 K - 6)

are three continuous terms of AP

As the difference between any two consecutive terms of A.P is constant.

\Rightarrow (4 k - 6) - (k + 2) = (3 k - 6) - (4 k - 6)

\Rightarrow 3 k - 8 = - k

\Rightarrow 4 k = 8

\Rightarrow k = 2

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Question Text	Find the value of K so that $(K + 2), (4 K - 6)$ and $(3 K - 6)$ are three continuous terms of AP.
Answer Type	Text solution:1
Upvotes	150