Find the value of k if the points $A (2, 3), B (4, k) a n d C (6, 3)$ are collinear.

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Find the value of k if the points

A (2, 3), B (4, k) a n d C (6, 3)

are collinear.

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Text solutionVerified

Solution: area of

∠ A B C = 0

\frac{1}{2} (x_{3} (y_{1} - y_{2}) + x_{2} (y_{3} - y_{1}) + x_{1} (y_{2} - y_{3})) = 0

\frac{1}{2} (6 (3 - k) + 4 (- 3 - 3) + 2 (k + 3)) = 0

18 - 6 k - 24 + 2 k + 6 = 0

k=0

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Question Text	Find the value of k if the points $A (2, 3), B (4, k) a n d C (6, 3)$ are collinear.
Answer Type	Text solution:1
Upvotes	150