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Find the slope of the tangent to the curve y = x^3-3x + 2 at t

Question

Find the slope of the tangent to the curve $y = x^{3} - 3 x + 2$ at the point whose $x$ coordinate is $3$ .

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Find the slope of the tangent to the curve

y = x^{3} - 3 x + 2

at the point whose

x

coordinate is

3

14 mins ago

Discuss this question LIVE

14 mins ago

Text solutionVerified

The given curve is

y = x^{3} - 3 x + 2

\Rightarrow \frac{d y}{d x} = 3 x^{2} - 3

Thus slope of the tangent to the given curve at

x = 3

(\frac{d y}{d x})_{x = 3} = (3 x^{2} - 3)_{x = 3} = 3 (3)^{2} - 3 = 24

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Question Text	Find the slope of the tangent to the curve $y = x^{3} - 3 x + 2$ at the point whose $x$ coordinate is $3$ .
Answer Type	Text solution:1
Upvotes	150