Find the image of the line 9x−1=−1y−2=−3z+3 in the plane 3x−3y+10z−26=0.

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Find the image of the line {{{x}-{1}}}{{9}}={{{y}-{2}}}{{-{1}}

Question

Find the image of the line $\frac{x - 1}{9} = \frac{y - 2}{- 1} = \frac{z + 3}{- 3}$ in the plane $3 x - 3 y + 10 z - 26 = 0 .$

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Charlotte Discussed

Find the image of the line

\frac{x - 1}{9} = \frac{y - 2}{- 1} = \frac{z + 3}{- 3}

in the plane

3 x - 3 y + 10 z - 26 = 0 .

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Question Text

Find the image of the line

\frac{x - 1}{9} = \frac{y - 2}{- 1} = \frac{z + 3}{- 3}

in the plane

3 x - 3 y + 10 z - 26 = 0 .