Find the equation of the plane passing through the straight line 2x−1=−3y+2=5z and perpendicular to the plane x−y+z+2=0.

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Find the equation of the plane passing through the straight li

Question

Find the equation of the plane passing through the straight line $\frac{x - 1}{2} = \frac{y + 2}{- 3} = \frac{z}{5}$ and perpendicular to the plane $x - y + z + 2 = 0 .$

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Daniel Discussed

Find the equation of the plane passing through the straight line

\frac{x - 1}{2} = \frac{y + 2}{- 3} = \frac{z}{5}

and perpendicular to the plane

x - y + z + 2 = 0 .

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Question Text

Find the equation of the plane passing through the straight line

\frac{x - 1}{2} = \frac{y + 2}{- 3} = \frac{z}{5}

and perpendicular to the plane

x - y + z + 2 = 0 .