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Find the equation of the normal to curve {x}^{{2}}={4}{y}which

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Find the equation of the normal to curve $x^{2} = 4 y$ which passes through the point (1, 2).

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Sebastian Discussed

Find the equation of the normal to curve

x^{2} = 4 y

which passes through the point (1, 2).

7 mins ago

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7 mins ago

Text solutionVerified

Solution:

h^{2} = 4 k

slope of normal

= - \frac{1}{\frac{d y}{d x}} = - \frac{2}{h}

equation of normal

(y - k) = - \frac{2}{h} (x - h)

k = 2 + \frac{2}{h} (1 - h)

\frac{h ^{2}}{4} = 2 + \frac{2}{h} (1 - h)

h=2
k=1
equation of line
(y-1)=-1(x-2)
x+y=3

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Question Text	Find the equation of the normal to curve $x^{2} = 4 y$ which passes through the point (1, 2).
Answer Type	Text solution:1
Upvotes	150