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Find the equation of the circle with centre (-a, -b) and radiu

Question

Find the equation of the circle with centre $(- a, - b)$ and radius $a^{2} - b^{2}$

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Find the equation of the circle with centre

(- a, - b)

and radius

a^{2} - b^{2}

9 mins ago

Discuss this question LIVE

9 mins ago

Text solutionVerified

Here it is given that centre

(h, k) = (- a, - b)

and radius

r = a^{2} - b^{2}

Therefore the equation of the circle is

(x + a)^{2} + (y + b)^{2} = (a^{2} - b^{2})^{2}

\Rightarrow x^{2} + 2 a x + a^{2} + y^{2} + 2 b y + b^{2} = a^{2} - b^{2}

\Rightarrow x^{2} + y^{2} + 2 a x + 2 b y + 2 b^{2} = 0

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Question Text	Find the equation of the circle with centre $(- a, - b)$ and radius $a^{2} - b^{2}$
Answer Type	Text solution:1
Upvotes	150