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Find the equation of a plane passing through the point (2, -1,

Question

Find the equation of a plane passing through the point $(2, - 1, 5)$ , perpendicular to the plane $x + 2 y - 3 z = 7$ and parallel to the line $\frac{x + 5}{3} = \frac{y + 1}{- 1} = \frac{z - 2}{1}$ .

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Levi Discussed

Find the equation of a plane passing through the point

(2, - 1, 5)

, perpendicular to the plane

x + 2 y - 3 z = 7

and parallel to the line

\frac{x + 5}{3} = \frac{y + 1}{- 1} = \frac{z - 2}{1}

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Question Text

Find the equation of a plane passing through the point

(2, - 1, 5)

, perpendicular to the plane

x + 2 y - 3 z = 7

and parallel to the line

\frac{x + 5}{3} = \frac{y + 1}{- 1} = \frac{z - 2}{1}

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