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Find the distance of the point {({1},{0},-{3})} from the plane

Question

Find the distance of the point $(1, 0, - 3)$ from the plane $x - y - z = 9$ measured parallel to the line $\frac{x - 2}{2} = \frac{y + 2}{2} = \frac{z - 6}{- 6} ˙$

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Find the distance of the point

(1, 0, - 3)

from the plane

x - y - z = 9

measured parallel to the line

\frac{x - 2}{2} = \frac{y + 2}{2} = \frac{z - 6}{- 6} ˙

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Question Text

Find the distance of the point

(1, 0, - 3)

from the plane

x - y - z = 9

measured parallel to the line

\frac{x - 2}{2} = \frac{y + 2}{2} = \frac{z - 6}{- 6} ˙

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