Find the distance of point $(2, 3, 4)$ from the plane $3 x + 2 y + 2 z + 5 = 0$ measured parallel to the line $\frac{x + 3}{3} = \frac{y - 2}{6} = \frac{z}{2}$

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Find the distance of point

(2, 3, 4)

from the plane

3 x + 2 y + 2 z + 5 = 0

measured parallel to the line

\frac{x + 3}{3} = \frac{y - 2}{6} = \frac{z}{2}

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Question Text

Find the distance of point

(2, 3, 4)

from the plane

3 x + 2 y + 2 z + 5 = 0

measured parallel to the line

\frac{x + 3}{3} = \frac{y - 2}{6} = \frac{z}{2}

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