Find the coordinates of the focus, axis, the equation of the directrix and latus rectum of the parabola $y^2=8x$.

Solution: Equation of parabola is,
$y^2=8x$
Comparing it with standard equation,$y^2=4ax$
We get, $a=2$.
As coefficient of $x$ is $8$ that is positive.
$\therefore$ Given parabola will be open with x-direction.
Focus of parabola $=\left(a,0\right)=\left(2,0\right)$
Equation of directrix , $x=-a\Rightarrow x=-2\Rightarrow x+2=0$
Latus rectum of parabola ,$=4a=8$