Find the centre and radius of the circle $(x+5){}^2+(y-3){}^2=36$

The equation of the given circle is,
$(x+5){}^2+(y-3){}^2=36$
$\Rightarrow {\left\{x-\left(-5\right)\right\}}^2+{\left(y-3\right)}^2=6^2$
which is of the form $(x-h){}^2+(y-k){}^2=r{}^2$
where $h=-5,k=3$ and $r=6$
Thus the centre of the given circle is $(-5,3)$ while its radius is $6$