Application of Integrals
Find the area of the circle which is interior to the parabola .
Solution: The required area is represented by the shaded area .
the given equation of circle, , and parabola, ,
we obtain the point of intersection as and .
It can be observed that the required area is symmetrical about -axis.
We draw perpendicular to .
Therefore, the coordinates of M are .
Therefore, Area Area - Area
Therefore, the required area is