Get 2 FREE Instant-Explanations on Filo with code FILOAPP

Find the area of ABC whose vertices are A(10, -6), B(2, 5) an

Question

Find the area of $Δ A BC$ whose vertices are $A (10, - 6), B (2, 5)$ and $C (- 1, 3)$ .

Views: 1,022 students

Found 6 tutors discussing this question

Sofia Discussed

Find the area of

Δ A BC

whose vertices are

A (10, - 6), B (2, 5)

and

C (- 1, 3)

7 mins ago

Discuss this question LIVE

7 mins ago

Text solutionVerified

Area of

Δ A BC

whose vertices are is

(x_{1}, y_{1}), (x_{2}, y_{2})

and

(x_{3}, y_{3})

are

Area of

Δ A BC = \frac{1}{2} [x_{1} (y_{2} - y_{3}) + x_{2} (y_{3} - y_{1}) + x_{3} (y_{1} - y_{2})]

Δ A BC

, vertices are

A (10, - 6), B (2, 5)

and

C (- 1, 3)

Area of triangle

= 1/2 (10 (5 - 3) + 2 (3 + 6) - 1 (- 6 - 5))

= 1/2 (20 + 18 + 11)

= 1/2 (49)

= 24.5

sq units.

Was this solution helpful?

150

Report

One destination to cover all your homework and assignment needs

Learn Practice Revision Succeed

Instant 1:1 help, 24x7

60, 000+ Expert tutors

Textbook solutions

Big idea maths, McGraw-Hill Education etc

Essay review

Get expert feedback on your essay

Schedule classes

High dosage tutoring from Dedicated 3 experts

Trusted by 4 million+ students

Stuck on the question or explanation?

Connect with our math tutors online and get step by step solution of this question.

231 students are taking LIVE classes

Question Text	Find the area of $Δ A BC$ whose vertices are $A (10, - 6), B (2, 5)$ and $C (- 1, 3)$ .
Answer Type	Text solution:1
Upvotes	150