Find the angle between the vectors i^−2j^+3kand 3i^−2j^+k

Solution: =(i^−2j^+3k^)⋅(3i^−2j^+k^)=3+3+3=14⋅14cosθ=1410=cosθ=θ=cos−1(75)

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Find the angle between the vectors {{i}}-{2}{{j}}+{3}{k}and {3

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Find the angle between the vectors $\hat{i} - 2 \hat{j} + 3 k$ and $3 \hat{i} - 2 \hat{j} + k$

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Henry Discussed

Find the angle between the vectors

\hat{i} - 2 \hat{j} + 3 k

and

3 \hat{i} - 2 \hat{j} + k

5 mins ago

Discuss this question LIVE

5 mins ago

Solution: =

(\hat{i} - 2 \hat{j} + 3 \hat{k}) \cdot (3 \hat{i} - 2 \hat{j} + \hat{k})

3 + 3 + 3 = 14 \cdot 14 cos θ

\frac{10}{14} = cos θ

θ = cos^{- 1} (\frac{5}{7})

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Question Text	Find the angle between the vectors $\hat{i} - 2 \hat{j} + 3 k$ and $3 \hat{i} - 2 \hat{j} + k$
Answer Type	Text solution:1
Upvotes	150