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Find (i) The lateral or curved surface area of a closed cylind

Question

Find
(i) The lateral or curved surface area of a closed cylindrical petrol storage tank that is $4.2 m$ in diameter and $4.5 m$ high.
(ii) How much steel was actually used, if $\frac{1}{12}$ of the steel actually used was wasted in making the tank?

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Find
(i) The lateral or curved surface area of a closed cylindrical petrol storage tank that is

4.2 m

in diameter and

4.5 m

high.
(ii) How much steel was actually used, if

\frac{1}{12}

of the steel actually used was wasted in making the tank?

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Text solutionVerified

(i)

Diameter of a cylindrical(closed) petrol tank

= 4.2 m

Radius

= \frac{4.2}{2} = 2.1 m

Height

= 4.5 m

Curved Surface area

= 2 π r h = 2 \times \frac{22}{7} \times 2.1 \times 4.5 = 59.4 s q . m

(ii)

Total surface area

= 2 π r (r + h) = 2 \times \frac{22}{7} \times 2.1 \times (2.1 + 4.5) = 2 \times \frac{22}{7} \times 2.1 \times 6.6 = 87.12 s q . m

Let the amount of steel used in making the tank

= x

Steel wasted

= \frac{x}{12}

Given:Amount of steel required

-

Amount of steel wasted

=

T.S.A of the tank.

\Rightarrow x - \frac{x}{12} = 87.12

\Rightarrow \frac{12 x - x}{12} = 87.12

\Rightarrow \frac{11 x}{12} = 87.12

\Rightarrow x = \frac{12}{11} \times 87.12 = 95.04 s q . m

∴ 95.04 s q . m

steel was used in actual while making such a tank.

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Question Text	Find (i) The lateral or curved surface area of a closed cylindrical petrol storage tank that is $4.2 m$ in diameter and $4.5 m$ high. (ii) How much steel was actually used, if $\frac{1}{12}$ of the steel actually used was wasted in making the tank?
Answer Type	Text solution:1
Upvotes	150