Find a relation between x and y such that the point (x ,y) is equidistant from the points (7, 1) and (3, 5).

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Text solutionVerified

Solution: PB=PC

(x - 7)^{2} + (y - 1)^{2} = (x - 3)^{2} + (y - 5)^{2}

squaring both sides and solving it

x^{2} - 14 x + 49 + y^{2} - 2 y + 1 = x^{2} - 6 x + 9 + y^{2} - 10 y + 25

8 y + 16 = 8 x

y = x - 2

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Question Text	Find a relation between x and y such that the point (x ,y) is equidistant from the points (7, 1) and (3, 5).
Answer Type	Text solution:1
Upvotes	150