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Factorise: (i) 12x^2-7x-1 (ii) 2x^2+7x+3 (iii) 6x^2+5x-6 (iv)

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Factorise:
(i) $12 x^{2} - 7 x - 1$
(ii) $2 x^{2} + 7 x + 3$
(iii) $6 x^{2} + 5 x - 6$
(iv) $3 x^{2} - x - 4$

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Samuel Discussed

Factorise:
(i)

12 x^{2} - 7 x - 1

(ii)

2 x^{2} + 7 x + 3

(iii)

6 x^{2} + 5 x - 6

(iv)

3 x^{2} - x - 4

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Text solutionVerified

(i)

12 x^{2} - 7 x + 1

= 12 x^{2} - 4 x - 3 x + 1

= 4 x (3 x - 1) - 1 (3 x - 1)

= (4 x - 1) (3 x - 1)

(ii)

2 x^{2} + 7 x + 3

= 2 x^{2} + 6 x + x + 3

= 2 x (x + 3) + 1 (x + 3)

= (2 x + 1) (x + 3)

(iii)

6 x^{2} + 5 x - 6

= 6 x^{2} + 9 x - 4 x - 6

= 3 x (2 x + 3) - 2 (2 x + 3)

= (3 x - 2) (2 x + 3)

(iv))

3 x^{2} - x - 4

= 3 x^{2} - 4 x + 3 x - 4

= x (3 x - 4) + 1 (3 x - 4)

= (3 x - 4) (x + 1)

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Question Text	Factorise: (i) $12 x^{2} - 7 x - 1$ (ii) $2 x^{2} + 7 x + 3$ (iii) $6 x^{2} + 5 x - 6$ (iv) $3 x^{2} - x - 4$
Answer Type	Text solution:1
Upvotes	150