Evaluate (n−r)!n!, when(i) n=6,r=2.(ii) n=9,r=5

We need to find value of (n−r)!n!i) Given, n=6,r=2∴(n−r)!n!=(6−2)!6!=4!6!=4!6×5×4!=30ii) Given, n=9,r=5Therefore the value of (n−r)!n!=(9−5)!9!=4!9!=4!9×8×7×6×5×4!=9×8×7×6×5=15120

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Evaluate {n!}{(n-r)!}, when (i) n = 6, r = 2. (ii) n=9, r=5

Question

Evaluate $\frac{n !}{( n - r )!}$ , when
(i) $n = 6, r = 2$ .
(ii) $n = 9, r = 5$

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Chloe Discussed

Evaluate

\frac{n !}{( n - r )!}

, when
(i)

n = 6, r = 2

(ii)

n = 9, r = 5

7 mins ago

Discuss this question LIVE

7 mins ago

Text solutionVerified

We need to find value of

\frac{n !}{( n - r )!}

i) Given,

n = 6, r = 2

∴ \frac{n !}{( n - r )!} = \frac{6 !}{( 6 - 2 )!}

= \frac{6 !}{4 !}

= \frac{6 \times 5 \times 4 !}{4 !} = 30

ii) Given,

n = 9, r = 5

Therefore the value of

\frac{n !}{( n - r )!} = \frac{9 !}{( 9 - 5 )!} = \frac{9 !}{4 !} = \frac{9 \times 8 \times 7 \times 6 \times 5 \times 4 !}{4 !}

= 9 \times 8 \times 7 \times 6 \times 5 = 15120

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Question Text	Evaluate $\frac{n !}{( n - r )!}$ , when (i) $n = 6, r = 2$ . (ii) $n = 9, r = 5$
Answer Type	Text solution:1
Upvotes	150

Evaluate (n−r)!n!​, when(i) n=6,r=2.(ii) n=9,r=5

Text solutionVerified

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Evaluate $\frac{n !}{( n - r )!}$ , when
(i) $n = 6, r = 2$ .
(ii) $n = 9, r = 5$