Each of the $n$ urns contains 4 white and 6 black balls. The $(n + 1)$ th urn contains 5 white and 5 black balls. One of the $n + 1$ urns is chosen at random and two balls are drawn from it without replacement. Both the balls turn out to be black. If the probability that the $(n + 1)$ th urn was chosen to draw the balls is 1/16, then find the value of $n$ .

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Each of the

n

urns contains 4 white and 6 black balls. The

(n + 1)

th urn contains 5 white and 5 black balls. One of the

n + 1

urns is chosen at random and two balls are drawn from it without replacement. Both the balls turn out to be black. If the probability that the

(n + 1)

th urn was chosen to draw the balls is 1/16, then find the value of

n

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