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Consider two regions: {R}_{{1}}: Point {P} is nearer to {({1},

Question

Consider two regions: $R_{1} :$ Point $P$ is nearer to $(1, 0)$ then to $x = - 1$ $R_{2} :$ Point $P$ is nearer to $(0, 0)$ then to $(8, 0)$ Statement 1 : The area of the region common to $R_{1} a n d R_{2}$ is $\frac{128}{3} s q \overset{u}{˙} n i t s$ Statement 2 : The area bounded by $x = 4 y a n d y = 4$ is $\frac{32}{3} s q \overset{u}{˙} n i t s$

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Scarlett Discussed

Consider two regions:

R_{1} :

Point

P

is nearer to

(1, 0)

then to

x = - 1

R_{2} :

Point

P

is nearer to

(0, 0)

then to

(8, 0)

Statement 1 : The area of the region common to

R_{1} a n d R_{2}

\frac{128}{3} s q \overset{u}{˙} n i t s

Statement 2 : The area bounded by

x = 4 y a n d y = 4

\frac{32}{3} s q \overset{u}{˙} n i t s

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Question Text

Consider two regions:

R_{1} :

Point

P

is nearer to

(1, 0)

then to

x = - 1

R_{2} :

Point

P

is nearer to

(0, 0)

then to

(8, 0)

Statement 1 : The area of the region common to

R_{1} a n d R_{2}

\frac{128}{3} s q \overset{u}{˙} n i t s

Statement 2 : The area bounded by

x = 4 y a n d y = 4

\frac{32}{3} s q \overset{u}{˙} n i t s

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