Consider a set of point R in which is at a distance of 2 units from the line 1x=−1y−1=2z+2 between the planes x−y+2z=3=0andx−y+2z−2=0.

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Consider a set of point R in which is at a distance of 2 units

Question

Consider a set of point R in which is at a distance of 2 units from the line $\frac{x}{1} = \frac{y - 1}{- 1} = \frac{z + 2}{2}$ between the planes $x - y + 2 z = 3 = 0 and x - y + 2 z - 2 = 0 .$

The volume of the bounded figure by points R and the planes is

(10 / 33) π

cube units.

The area of the curved surface formed by the set of points R is

(20 π / 6)

sq. units.

The volume of the bounded figure by the set of points R and the planes is

(20 π / 6)

cubic units.

The area of the curved surface formed by the set of points R is

(10 / 3) π

sq. units.

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Consider a set of point R in which is at a distance of 2 units from the line

\frac{x}{1} = \frac{y - 1}{- 1} = \frac{z + 2}{2}

between the planes

x - y + 2 z = 3 = 0 and x - y + 2 z - 2 = 0 .

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Question Text	Consider a set of point R in which is at a distance of 2 units from the line $\frac{x}{1} = \frac{y - 1}{- 1} = \frac{z + 2}{2}$ between the planes $x - y + 2 z = 3 = 0 and x - y + 2 z - 2 = 0 .$
Answer Type	Video solution: 1
Upvotes	150