An integrating factor of the differential equation sinxdydx+2ycosx=1 is

sin2x

2sinx

log|sinx|

1sin2x

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[a] Given differential equation is sinxdydx+2ycosx=1;⇒dydx+2ycosxsinx=1sinx ⇒dydx+(2cotx)y=cosecx I.F. =e∫2cotxdx=e∫2(cosxsinx)dx=e2logsinx =eloge(sinx)2=(sinx)2

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Question Text	An integrating factor of the differential equation sinxdydx+2ycosx=1 is
Answer Type	Text solution:1
Upvotes	150

An integrating factor of the differential equation sinxdydx+2ycosx=1 is

Text solutionVerified

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